~/coding-interview/leetcode-solution-reverse-string.md

Reverse String - Leet Code Solution

// TL;DR

Two-pointer swap — start from both ends, swap characters, move inward until pointers meet. O(n) time, O(1) space.

Reverse String - Leet Code Solution

Problem Statement

Write a function that reverses a string. The input string is given as an array of characters char[].

Do not allocate extra space for another array, you must do this by modifying the input array in-place with O(1) extra memory.

You may assume all the characters consist of printable ascii characters.

Example

Input: ["h","e","l","l","o"]
Output: ["o","l","l","e","h"]

Solution

Its very simple problem to solve.

  • Take two index variables
  • Start one from left, other from extreme end
  • Start swapping their values, and move them
    Left in forward, and extreme right in backward
  • Repeat above untill both index variables cross each other

Code

public void reverseString(char[] s) {
   int left = 0;
   int end = s.length-1;
   while (left < end) {
      //swap
      char temp = s[left];
      s[left] = s[end];
      s[end] = temp;
      
      left ++;
      end --;
   }
}

Complexity

Its O(n)

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